EXCEPT that the sql code is not executing correctly. The date field is
in the table always shows "12/1/1899 11:59:17 PM" no other date. I'm
should have the date of the input into the function + or - the integer
in the task_due_days field.
for example (cdate("1/1/2002")+30) as task_due_date
What am I doing wrong?
Function SetTasks(trans_id As Long, trans_type As Integer, event_date
As Date)
Dim task As String
task = "Insert into tbl_tasks
(trans_id,task_name,Task_due_date,comments) SELECT (" & trans_id & ")
as trans_id,task_name,(cdate(" & event_date & ")+[task_due_days]) as
task_due_date,comments FROM tbl_task_parameter WHERE trans_type=" &
trans_type
Debug.Print task
DoCmd.RunSQL (task)
End Function
the actual SQL code is....
Insert into tbl_tasks (trans_id,task_name,Task_due_date,comments)
SELECT (192) as trans_id,task_name,(cdate(1/1/2001)+[task_due_days]) as
task_due_date,comments FROM tbl_task_parameter WHERE trans_type=1
ANY HELP IS GREATLY APPRECIATED!(stoppal@.hotmail.com) writes:
> the actual SQL code is....
> Insert into tbl_tasks (trans_id,task_name,Task_due_date,comments)
> SELECT (192) as trans_id,task_name,(cdate(1/1/2001)+[task_due_days]) as
> task_due_date,comments FROM tbl_task_parameter WHERE trans_type=1
Apparently you are not using SQL Server, as there is no cdate function
in SQL Serever.
I can tell what the problem is though: 1/1/2001 = 0 with integer division,
and with floating-point division you get 0.0005. Since you got
11:59:17, I guess that in whatever you are using, you have floating-
point division. (In SQL Server you would get integer division here.)
So you need to delimit the date string. In SQL Server that would be
'1/1/2001'. But it looks a bit likely you are using Access, in which
case maybe ## is better. But you better ask in comp.databases.ms-access
it you are uncertain.
--
Erland Sommarskog, SQL Server MVP, esquel@.sommarskog.se
Books Online for SQL Server SP3 at
http://www.microsoft.com/sql/techin.../2000/books.aspsql
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